Question

The radius of two metallic spheres A and B are $ {{r}_{1}} $ and $ {{r}_{2}} $ respectively $ ({{r}_{1}}>{{r}_{2}}). $ They are connected by a thin wire and the system is given a certain charge. The charge will be greater

• A. equal on both
• B. zero on both
• C. on the surface of sphere A
• D. on the surface of sphere B

Answer 1

Answer: (C)

When the spheres are connected by a wire, then potential on both becomes equal.
$ \therefore $ $ \frac{{{Q}_{1}}}{{{r}_{1}}}=\frac{{{Q}_{2}}}{{{r}_{2}}} $
$ \Rightarrow $ $ \frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}} $
When $ {{r}_{1}}>{{r}_{2}}, $ then $ {{Q}_{1}}>{{Q}_{2}} $