The radius of the second Bohr orbit for hydrogen atom is: (Planck's Const. h =6 . 6262 × 10-34 Js; mass of electron =9 . 1091 × 10-31 Kg charge of electron e =1 .60210 × 10-19 C; permittivity of vacuum .(ϵ0)=8 ⋅ 854185 × 10-12 Kg -1 m -3 A 2)

Question

The radius of the second Bohr orbit for hydrogen atom is: (Planck's Const. h =6 . 6262 × 10-34 Js; mass of electron =9 . 1091 × 10-31 Kg charge of electron e =1 .60210 × 10-19 C; permittivity of vacuum .(ϵ0)=8 ⋅ 854185 × 10-12 Kg -1 m -3 A 2) (A) 0.529 mathringA (B) 2.12 mathringA (C) 1.65 mathringA (D) 4.76 mathringA

Tardigrade Admin · Accepted Answer

r= a0 (n2/Z)= 0.529×4 =2.12 mathringA

$0.529 \overset{˚}{A}$

$2.12 \overset{˚}{A}$

$1.65 \overset{˚}{A}$

$4.76 \overset{˚}{A}$

$r = a_{0} \frac{n ^{2}}{Z} = 0.529 \times 4$

$= 2.12 \overset{˚}{A}$

Q. The radius of the second Bohr orbit for hydrogen atom is: (Planck's Const. h=6.6262×10−34Js; mass of electron =9.1091×10−31Kg charge of electron e=1.60210×10−19C; permittivity of vacuum (ϵ0​)=8⋅854185×10−12Kg−1m−3A2)

0.529A˚

2.12A˚

1.65A˚

4.76A˚

r=a0​Zn2​=0.529×4 =2.12A˚

$0.529 \overset{˚}{A}$

$2.12 \overset{˚}{A}$

$1.65 \overset{˚}{A}$

$4.76 \overset{˚}{A}$

$r = a_{0} \frac{n ^{2}}{Z} = 0.529 \times 4$

$= 2.12 \overset{˚}{A}$