The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate α. Resistance per unit length of the loop is ρ. Then current in wire AB is ( AB is one of the diameters)

Question

The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate α. Resistance per unit length of the loop is ρ. Then current in wire AB is ( AB is one of the diameters) (A) (R α/2 ρ) from A to B (B) (R α/2 ρ) from B to A (C) (2 R α/ρ) from A to B (D) Zero

Tardigrade Admin · Accepted Answer

The induced current in upper semicircular and lower semicircular will cancel each other in diameter (AB).

Q. The radius of the circular conducting loop shown in figure is $R$ . Magnetic field is decreasing at a constant rate $α$ . Resistance per unit length of the loop is $ρ$ . Then current in wire $A B$ is ( $A B$ is one of the diameters)

$\frac{R α}{2 ρ}$ from $A$ to $B$

$\frac{R α}{2 ρ}$ from $B$ to $A$

$\frac{2 R α}{ρ}$ from $A$ to $B$

Zero

The induced current in upper semicircular and lower semicircular will cancel each other in diameter $(A B)$ .

Q. The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate α. Resistance per unit length of the loop is ρ. Then current in wire AB is ( AB is one of the diameters)

2ρRα​ from A to B

2ρRα​ from B to A

ρ2Rα​ from A to B