The radius of R of a nucleus of mass number A can be estimated by the formula R =(1.3 × 10-15) A 1 / 3 m It follows that the mass density of a nucleus is of the order of: ( M text prot. ≅ M text neut. ≃ 1.67 × 10-27 kg )

Question

The radius of R of a nucleus of mass number A can be estimated by the formula R =(1.3 × 10-15) A 1 / 3 m It follows that the mass density of a nucleus is of the order of: ( M text prot. ≅ M text neut. ≃ 1.67 × 10-27 kg ) (A) 1024 kg m -3 (B) 103 kg m -3 (C) 1017 kg m -3 (D) 1010 kg m -3

Tardigrade Admin · Accepted Answer

ρ text nucleus =( text mass / text volume )=( A /(4 / 3) π r 03 A ) =(3/4 π t 03)=2.3 × 1017 kg / m 3

Q. The radius of $R$ of a nucleus of mass number A can be estimated by the formula $R = (1.3 \times 1 0^{- 15}) A^{1/3} m$ It follows that the mass density of a nucleus is of the order of:
$(M_{prot.} ≅ M_{neut.} ≃ 1.67 \times 1 0^{- 27} k g)$

$1 0^{24} k g m^{- 3}$

$1 0^{3} k g m^{- 3}$

$1 0^{17} k g m^{- 3}$

$1 0^{10} k g m^{- 3}$

$ρ_{nucleus} = \frac{mass}{volume} = \frac{A}{( 4/3 ) π r _{0}^{3} A}$
$= \frac{3}{4 π t _{0}^{3}} = 2.3 \times 1 0^{17} k g / m^{3}$

Q. The radius of R of a nucleus of mass number A can be estimated by the formula R=(1.3×10−15)A1/3m It follows that the mass density of a nucleus is of the order of: (Mprot. ​≅Mneut. ​≃1.67×10−27kg)

1024kgm−3

103kgm−3

1017kgm−3

1010kgm−3