The radius of Li++ ion in its ground state in terms of Bohr radius a0 is

Question

The radius of Li++ ion in its ground state in terms of Bohr radius a0 is (A) a0 (B) (a0/3) (C) 2a0 (D) 3a0

Tardigrade Admin · Accepted Answer

Radius of nth orbit of hydrogen-like atom is rn = (n2/Z) a0 For Li++ ion, Z = 3, n = 1 for ground state ∴ Radius of Li++ ion in its ground state is r1 = ((1)2/3)a0 = (a0/3)

Q. The radius of $L i^{++}$ ion in its ground state in terms of Bohr radius $a_{0}$ is

$a_{0}$

$\frac{a _{0}}{3}$

$2 a_{0}$

$3 a_{0}$

Radius of $n^{t h}$ orbit of hydrogen-like atom is
$r_{n} = \frac{n ^{2}}{Z} a_{0}$
For $L i^{++}$ ion, $Z = 3, n = 1$ for ground state
$∴$ Radius of $L i^{++}$ ion in its ground state is
$r_{1} = \frac{( 1 ) ^{2}}{3} a_{0} = \frac{a _{0}}{3}$

Q. The radius of Li++ ion in its ground state in terms of Bohr radius a0​ is

a0​

3a0​​

2a0​

3a0​