The radius of hydrogen atom in the ground state is 0.53 mathringA . The radius of Li2+ ion (atomic number = 3 ) in a similar state is :

Question

The radius of hydrogen atom in the ground state is 0.53 mathringA . The radius of Li2+ ion (atomic number = 3 ) in a similar state is : (A)  0.176 mathringA (B)  0.30 mathringA (C)  0.53 mathringA (D)  1.23 mathringA

Tardigrade Admin · Accepted Answer

r4=(r0 × n2/Z) Given, r0= radius of H atom in ground state =0.5 mathringA n= number of orbit =1 Z= Atomic number of Li =3 ∴ r4=(0.53 × 12/3) =0.176 mathringA

Q. The radius of hydrogen atom in the ground state is $0.53 \overset{˚}{A}$ . The radius of $L i^{2 +}$ ion (atomic number $= 3$ ) in a similar state is :

$0.176 \overset{˚}{A}$

$0.30 \overset{˚}{A}$

$0.53 \overset{˚}{A}$

$1.23 \overset{˚}{A}$

$r_{4} = \frac{r _{0} \times n ^{2}}{Z}$

Given, $r_{0} =$ radius of $H$ atom in ground state $= 0.5 \overset{˚}{A}$

$n =$ number of orbit $= 1$

$Z =$ Atomic number of $L i = 3$

$∴ r_{4} = \frac{0.53 \times 1 ^{2}}{3}$

$= 0.176 \overset{˚}{A}$

Q. The radius of hydrogen atom in the ground state is 0.53A˚ . The radius of Li2+ ion (atomic number =3 ) in a similar state is :

0.176A˚

0.30A˚

0.53A˚

1.23A˚