The radius of aluminium nucleus (in fermi) is nearly

Question

The radius of aluminium nucleus (in fermi) is nearly (A) 1.5 (B) 2.5 (C) 4.5 (D) 13.5

Tardigrade Admin · Accepted Answer

The radius (R) of the nucleus of any metal is R=R0 A1 / 3 where A is atomic number, and R0=1.5 fermi For aluminium A=27 ∴ R =1.5 ×(27)1 / 3 =1.5 × 3=4.5 fermi

Q. The radius of aluminium nucleus (in fermi) is nearly

1.5

2.5

4.5

13.5

The radius $(R)$ of the nucleus of any metal is
$R = R_{0} A^{1/3}$
where $A$ is atomic number, and $R_{0} = 1.5$ fermi
For aluminium $A = 27$
$∴ R = 1.5 \times (27)^{1/3}$
$= 1.5 \times 3 = 4.5$ fermi

Q. The radius of aluminium nucleus (in fermi) is nearly

1.5

2.5

4.5

13.5

The radius (R) of the nucleus of any metal is R=R0​A1/3 where A is atomic number, and R0​=1.5 fermi For aluminium A=27 ∴R=1.5×(27)1/3 =1.5×3=4.5 fermi

The radius $(R)$ of the nucleus of any metal is
$R = R_{0} A^{1/3}$
where $A$ is atomic number, and $R_{0} = 1.5$ fermi
For aluminium $A = 27$
$∴ R = 1.5 \times (27)^{1/3}$
$= 1.5 \times 3 = 4.5$ fermi