Question

The radioactive isotope ${}_{27}^{60}Co$ which is used in the treatment of cancer can be made by (n, p) reaction. For this reaction the target nucleus is

• A. ${}_{28}^{58}Ni$
• B. ${}_{27}^{59}Co$
• C. ${}_{28}^{60}Ni$
• D. ${}_{27}^{60}Co$

Answer 1

Answer: (C)

${}_{28}N{i}^{60}+{}_0{n}^1\to {}_{27}C{o}^{60}+{}_1{H}^1$ (n, p means that neutron attacks and proton liberates).