The radio transmitter operates on a wavelength of 1500 m at a power of 400 kW. The energy of radio photon (in joule) is

Question

The radio transmitter operates on a wavelength of 1500 m at a power of 400 kW. The energy of radio photon (in joule) is (A)  1.32 × 10- 24 J (B)  1.32 × 10- 28 J (C)  1.32 × 10- 26 J (D)  1.32 × 10- 32 J

Tardigrade Admin · Accepted Answer

According to Planck's quantum theory, a source of radiation emits energy in the form of photons, which travel in straight line.
The energy photon is E = hv =

\frac{h c}{λ}

Hence energy of radio photon is
E =

6.6 \times 1 0^{- 34} \times 2 \times 1 0^{5}

J

[∵ v = \frac{c}{λ} = \frac{3 \times 1 0 ^{8}}{1500} = 2 \times 1 0^{5} Hz]

∴ E = 1.32 \times 1 0^{- 28}

J

Q. The radio transmitter operates on a wavelength of 1500 m at a power of 400 kW. The energy of radio photon (in joule) is

$1.32 \times 1 0^{- 24}$ J

$1.32 \times 1 0^{- 28}$ J

$1.32 \times 1 0^{- 26}$ J

$1.32 \times 1 0^{- 32}$ J

Q. The radio transmitter operates on a wavelength of 1500 m at a power of 400 kW. The energy of radio photon (in joule) is

1.32×10−24 J

1.32×10−28 J

1.32×10−26 J

1.32×10−32 J

According to Planck's quantum theory, a source of radiation emits energy in the form of photons, which travel in straight line. The energy photon is E = hv = λhc​ Hence energy of radio photon is E = 6.6×10−34×2×105 J [∵v=λc​=15003×108​=2×105Hz] ∴E=1.32×10−28 J

$1.32 \times 1 0^{- 24}$ J

$1.32 \times 1 0^{- 28}$ J

$1.32 \times 1 0^{- 26}$ J

$1.32 \times 1 0^{- 32}$ J