The radical axis of the pairs of circles x2+y2=144 and x2+y2-15 x+11 y=0, is

Question

The radical axis of the pairs of circles x2+y2=144 and x2+y2-15 x+11 y=0, is (A) 15 x+11 y-144=0 (B) 15 x-11 y+144=0 (C) 15 x-11 y-144=0 (D) None of these

Tardigrade Admin · Accepted Answer

The equations of the circle are S 1= x 2+ y 2-144=0 S 2= x 2+ y 2-15 x +11 y =0 ∴ The equation of the radical axis is S 1- S 2=0 ⇒ ( x 2+ y 2-144)-( x 2+ y 2-15 x +11 y )=0 or 15 x - 11 y -144=0 So, the required equation is 15 x-11 y-144=0.

Q. The radical axis of the pairs of circles $x^{2} + y^{2} = 144$ and $x^{2} + y^{2} - 15 x + 11 y = 0$ , is

$15 x + 11 y - 144 = 0$

$15 x - 11 y + 144 = 0$

$15 x - 11 y - 144 = 0$

None of these

Q. The radical axis of the pairs of circles x2+y2=144 and x2+y2−15x+11y=0, is

15x+11y−144=0

15x−11y+144=0

15x−11y−144=0

None of these

The equations of the circle are S1​=x2+y2−144=0 S2​=x2+y2−15x+11y=0 ∴ The equation of the radical axis is S1​−S2​=0 ⇒(x2+y2−144)−(x2+y2−15x+11y)=0 or 15x−11y−144=0 So, the required equation is 15x−11y−144=0.

Q. The radical axis of the pairs of circles $x^{2} + y^{2} = 144$ and $x^{2} + y^{2} - 15 x + 11 y = 0$ , is

$15 x + 11 y - 144 = 0$

$15 x - 11 y + 144 = 0$

$15 x - 11 y - 144 = 0$