The radiation force experienced by body exposed to radiation of intensity I, assuming surface of body to be perfectly absorbing is:

Question

The radiation force experienced by body exposed to radiation of intensity I, assuming surface of body to be perfectly absorbing is: (A) (π R2 I/c) (B) (π R2 I/2 c) (C) (I R H/2 c) (D) (I R H/c)

Tardigrade Admin · Accepted Answer

Radiation force (2 I/c) × text Area =(I/c) ⋅ (1/2) ⋅ 2 R . H=(I R H/c)

Q. The radiation force experienced by body exposed to radiation of intensity $I$ , assuming surface of body to be perfectly absorbing is:

$\frac{π R ^{2} I}{c}$

$\frac{π R ^{2} I}{2 c}$

$\frac{I R H}{2 c}$

$\frac{I R H}{c}$

Radiation force
$\frac{2 I}{c} \times Area = \frac{I}{c} \cdot \frac{1}{2} \cdot 2 R . H = \frac{I R H}{c}$

Q. The radiation force experienced by body exposed to radiation of intensity I, assuming surface of body to be perfectly absorbing is:

cπR2I​

2cπR2I​

2cIRH​

cIRH​