The radiation corresponding to the transitions of electrons from n=2 to n=1 of hydrogen atoms, fall on He+ ions which are in n=1 and n=2 states. The possible transition of helium ions as they absorb energy from the radiation is

Question

The radiation corresponding to the transitions of electrons from n=2 to n=1 of hydrogen atoms, fall on He+ ions which are in n=1 and n=2 states. The possible transition of helium ions as they absorb energy from the radiation is (A) n=2 arrow n=3 (B) n=1 arrow n=4 (C) n=2 arrow n=5 (D) n=2 arrow n=4

Tardigrade Admin · Accepted Answer

E=13.6× 1× ((1/12) - (1/22))=10.2eV For He+ in n=2 , 10.2eV=13.6× 4((1/22) - (1/n2)) ⇒ n=4

Q. The radiation corresponding to the transitions of electrons from $n = 2$ to $n = 1$ of hydrogen atoms, fall on $H e^{+}$ ions which are in $n = 1$ and $n = 2$ states. The possible transition of helium ions as they absorb energy from the radiation is

$n = 2 \to n = 3$

$n = 1 \to n = 4$

$n = 2 \to n = 5$

$n = 2 \to n = 4$

$E = 13.6 \times 1 \times (\frac{1}{1 ^{2}} - \frac{1}{2 ^{2}}) = 10.2 e V$
For $H e^{+}$ in $n = 2$ ,
$10.2 e V = 13.6 \times 4 (\frac{1}{2 ^{2}} - \frac{1}{n ^{2}})$
$\Rightarrow n = 4$

Q. The radiation corresponding to the transitions of electrons from n=2 to n=1 of hydrogen atoms, fall on He+ ions which are in n=1 and n=2 states. The possible transition of helium ions as they absorb energy from the radiation is

n=2→n=3

n=1→n=4

n=2→n=5

n=2→n=4