Question

The quadratic equation $2x^2-\left(a^3+8a-1\right)x+a^2-4a=0$ possesses roots of opposite sign. Then

• A. $a\le 0$
• B. $0<a<4$
• C. $4\le a<8$
• D. $a\ge 8$

Answer 1

Answer: (B)

Since, roots are opposite sign.
$\therefore$ Product of the roots $<0$
$\Rightarrow a^2-4a<0$
$\Rightarrow a(a-4)<0$
$\Rightarrow 0<a<4$