r=3i^−j^​+t(i^+2j^​+3k^) ∴ a vector parallel to the given line is b=i^+2j^​+3k^ ∴ unit vector along the line =1+4+9​i^+2j^​+3k^​=14​i^+2j^​+3k^​ ∴ projection =(i^+2j^​+3k^)⋅14​(i^+2j^​+3k^)​ =14​1+2+3​=14​6​