The product(s) obtained via oxymercuration (HgSO4+HgSO4) of 1-butyne would be

Question

The product(s) obtained via oxymercuration (HgSO4+HgSO4) of 1-butyne would be (A)  (B) CH3 -CH2 -CH2 -CHO (C) CH3 -CH2 -CHO+HCHO (D) CH3 -CH2 -COOH+HCOOH

Tardigrade Admin · Accepted Answer

Oxymercuration-demercuration brings about Markownikoff's addition of water as: CH3 - CH2- C ≡ C - H + H2SO4 xrightarrowHgSO4

Q. The product(s) obtained via oxymercuration $(H g S O_{4} + H g S O_{4})$ of $1$ -butyne would be

$C H_{3} - C H_{2} - C H_{2} - C H O$

$C H_{3} - C H_{2} - C H O + H C H O$

$C H_{3} - C H_{2} - COO H + H COO H$

Oxymercuration-demercuration brings about Markownikoff's addition of water as :
$C H_{3} - C H_{2} - C \equiv C - H + H_{2} S O_{4} H g S O_{4}$

Q. The product(s) obtained via oxymercuration (HgSO4​+HgSO4​) of 1-butyne would be

CH3​−CH2​−CH2​−CHO

CH3​−CH2​−CHO+HCHO

CH3​−CH2​−COOH+HCOOH

Oxymercuration-demercuration brings about Markownikoff's addition of water as : CH3​−CH2​−C≡C−H+H2​SO4​HgSO4​​

Q. The product(s) obtained via oxymercuration $(H g S O_{4} + H g S O_{4})$ of $1$ -butyne would be

$C H_{3} - C H_{2} - C H_{2} - C H O$

$C H_{3} - C H_{2} - C H O + H C H O$

$C H_{3} - C H_{2} - COO H + H COO H$

Oxymercuration-demercuration brings about Markownikoff's addition of water as :
$C H_{3} - C H_{2} - C \equiv C - H + H_{2} S O_{4} H g S O_{4}$