Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The product of all positive real values of x satisfying the equation x(16( log 5 x)3-68 log 5 x)=5-16 is
Q. The product of all positive real values of
x
satisfying the equation
x
(
16
(
l
o
g
5
x
)
3
−
68
l
o
g
5
x
)
=
5
−
16
is ______
917
134
JEE Advanced
JEE Advanced 2022
Report Error
Answer:
1
Solution:
x
16
(
l
o
g
5
x
)
3
−
68
l
o
g
5
x
=
5
−
16
Take
lo
g
to the base 5 on both sides and put
lo
g
5
x
=
t
16
t
4
−
68
t
2
+
16
=
0
⇒
4
t
4
−
17
t
2
+
4
=
0
⎩
⎨
⎧
t
1
t
2
t
3
t
4
t
1
+
t
2
+
t
3
+
t
4
=
0
lo
g
5
x
1
+
lo
g
5
x
2
+
lo
g
5
x
3
+
lo
g
5
x
4
=
0
x
1
x
2
x
3
x
4
=
1