Question

The product of additive inverses and multiplicative inverse of $\frac{x^2-4}{2x}$.

• A. -1
• B. 1
• C. $x^2-4$
• D. $x^2+4$

Answer 1

Answer: (A)

Additive inverse of a term $a$ is $-a$ and its multiplicative inverse is $1/a$
Therefore, additive inverse of $\frac{x^2-4}{2x}$ is $-\frac{x^2-4}{2x}$
and, multiplicative inverse is $\frac{x^2-4}{2x}$ is $\frac{2x}{x^2-4}$
Hence, required product of additive inverse and multiplicative inverse of the given term is $-\frac{x^2-4}{2x}\times \frac{2x}{x^2-4}=-1$