The probability that a bulb produced by a factory will fuse after 150 days if used is 0.50. What is the probability that out of 5 such bulbs none will fuse after 150 days of use?

Question

The probability that a bulb produced by a factory will fuse after 150 days if used is 0.50. What is the probability that out of 5 such bulbs none will fuse after 150 days of use? (A) 1-(19 / 20)5 (B) (19 / 20)5 (C) (3 / 4)5 (D) 90(1 / 4)5

Tardigrade Admin · Accepted Answer

Here p=19 / 20, q=1 / 20, n=5, r=5. The required probability is 5 C5((19/20))5((1/20))0=((19/20))5

Q. The probability that a bulb produced by a factory will fuse after $150$ days if used is $0.50$ . What is the probability that out of $5$ such bulbs none will fuse after $150$ days of use?

$1 - (19/20)^{5}$

$(19/20)^{5}$

$(3/4)^{5}$

$90 (1/4)^{5}$

Here $p = 19/20, q = 1/20, n = 5, r = 5$ . The required probability is
$^{5} C_{5} (\frac{19}{20})^{5} (\frac{1}{20})^{0} = (\frac{19}{20})^{5}$

Q. The probability that a bulb produced by a factory will fuse after 150 days if used is 0.50. What is the probability that out of 5 such bulbs none will fuse after 150 days of use?

1−(19/20)5

(19/20)5

(3/4)5

90(1/4)5