Question

The probability that $4^{\text{th }}$ power of a positive integer ends in the digit 6 is :

• A. $10\%$
• B. $20\%$
• C. $25\%$
• D. $40\%$

Answer 1

Answer: (D)

Natural number can end from 0 to 9 . Out of these 10 equally likely, ME and exhaustive cases, 4 cases e.g. $2,4,6$ and 8 are favourable $\Rightarrow P(r)=4/10]$