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Q. The probability that $4^{\text {th }}$ power of a positive integer ends in the digit 6 is :

Probability - Part 2

Solution:

Natural number can end from 0 to 9 . Out of these 10 equally likely, ME and exhaustive cases, 4 cases e.g. $2,4,6$ and 8 are favourable $\Rightarrow P(r)=4 / 10]$