The probability of getting the sum more than 7 when a pair of dice is tossed is

Question

The probability of getting the sum more than 7 when a pair of dice is tossed is (A) (1/9) (B) (1/4) (C) (7/12) (D) (5/12)

Tardigrade Admin · Accepted Answer

Sum of 7 can be obtained when (.2,6.),(.3,5.),(.3,6.),(.4,4.),(.4,5.),(.4,6.)(.5,3.),(.5,4.)(.5,5.)(.5,6.)(.6,2.)(.6,3.)(.6,4.)(.6,5.)(.6,6.) ∴ Probability of sum>7=(15/36)=(5/12)

Q. The probability of getting the sum more than $7$ when a pair of dice is tossed is

$\frac{1}{9}$

$\frac{1}{4}$

$\frac{7}{12}$

$\frac{5}{12}$

Sum of 7 can be obtained when $(2, 6), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6) (5, 3), (5, 4) (5, 5) (5, 6) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)$
$∴$ Probability of $s u m > 7 = \frac{15}{36} = \frac{5}{12}$

Q. The probability of getting the sum more than 7 when a pair of dice is tossed is

91​

41​

127​

125​