Question

The principal value of ${\sin }^{-1}\left(-\frac{\sqrt{3}}{2}\right)$ is :

• A. $-\frac{\pi }{3}$
• B. $\frac{\pi }{6}$
• C. $-\frac{2\pi }{3}$
• D. $\frac{2\pi }{3}$

Answer 1

Answer: (A)

${\sin }^{-1}\left(-\frac{\sqrt{3}}{2}\right)=\left[{\sin }^{-1}\sin \left(-\frac{\pi }{3}\right)\right]=-\frac{\pi }{3}$