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Q. The principal value of $\sin^{-1} \left( - \frac{\sqrt{3}}{2} \right)$ is :

Inverse Trigonometric Functions

Solution:

$\sin^{-1} \left( - \frac{\sqrt{3}}{2}\right) = \left[\sin^{-1} \sin\left( - \frac{\pi}{3}\right)\right] = - \frac{\pi}{3} $