The pressure of water in a water pipe when tap is opened and closed is respectively 3× 105N/m2 and 3.5× 105N/m2 .With open tap the velocity of water flowing is:

Question

The pressure of water in a water pipe when tap is opened and closed is respectively 3× 105N/m2 and 3.5× 105N/m2 .With open tap the velocity of water flowing is: (A) 10m/s (B) 5m/s (C) 20m/s (D) 15m/s

Tardigrade Admin · Accepted Answer

P1+(1/2)Ïv12=P2+(1/2)Ïv22(P1 - P2)=(1/2)Ïv22 Since tap is closed, v1 =0 (3 . 5 × (10)5 - 3 × (10)5)=(1/2)× (10)3× v2 v=10m/s

Q. The pressure of water in a water pipe when tap is opened and closed is respectively $3 \times 1 0^{5} N / m^{2}$ and $3.5 \times 1 0^{5} N / m^{2}$ .With open tap the velocity of water flowing is:

$10 m / s$

$5 m / s$

$20 m / s$

$15 m / s$

$P_{1} + \frac{1}{2} ρ v_{1}^{2} = P_{2} + \frac{1}{2} ρ v_{2}^{2} (P_{1} - P_{2}) = \frac{1}{2} ρ v_{2}^{2}$
Since tap is closed, v₁ $= 0$
$(3.5 \times (10)^{5} - 3 \times (10)^{5}) = \frac{1}{2} \times (10)^{3} \times v^{2}$
$v = 10 m / s$

Q. The pressure of water in a water pipe when tap is opened and closed is respectively 3×105N/m2 and 3.5×105N/m2 .With open tap the velocity of water flowing is:

10m/s

5m/s

20m/s

15m/s