The pressure exerted by an ideal gas on the walls of a container is

Question

The pressure exerted by an ideal gas on the walls of a container is (A) [(1/3)]r d of kinetic energy per unit volume of a gas (B) [(2/3)]r d of kinetic energy per unit volume of a gas (C) [(3/4)]t h of kinetic energy per unit volume of a gas (D) (3/2)× kinetic energy per unit volume of a gas

Tardigrade Admin · Accepted Answer

The pressure exerted by the gas on the walls of container is P=(1/3)ρ v2=(1/3)(m/V).v2× (2/2)=(2/3)(K E/V o l u m e)

Q. The pressure exerted by an ideal gas on the walls of a container is

$[\frac{1}{3}]^{r d}$ of kinetic energy per unit volume of a gas

$[\frac{2}{3}]^{r d}$ of kinetic energy per unit volume of a gas

$[\frac{3}{4}]^{t h}$ of kinetic energy per unit volume of a gas

$\frac{3}{2} \times$ kinetic energy per unit volume of a gas

The pressure exerted by the gas on the walls of container is
$P = \frac{1}{3} ρ v^{2} = \frac{1}{3} \frac{m}{V} . v^{2} \times \frac{2}{2} = \frac{2}{3} \frac{K E}{V o l u m e}$

Q. The pressure exerted by an ideal gas on the walls of a container is

[31​]rd of kinetic energy per unit volume of a gas

[32​]rd of kinetic energy per unit volume of a gas

[43​]th of kinetic energy per unit volume of a gas

23​× kinetic energy per unit volume of a gas

The pressure exerted by the gas on the walls of container is P=31​ρv2=31​Vm​.v2×22​=32​VolumeKE​

$[\frac{1}{3}]^{r d}$ of kinetic energy per unit volume of a gas

$[\frac{2}{3}]^{r d}$ of kinetic energy per unit volume of a gas

$[\frac{3}{4}]^{t h}$ of kinetic energy per unit volume of a gas

$\frac{3}{2} \times$ kinetic energy per unit volume of a gas

The pressure exerted by the gas on the walls of container is
$P = \frac{1}{3} ρ v^{2} = \frac{1}{3} \frac{m}{V} . v^{2} \times \frac{2}{2} = \frac{2}{3} \frac{K E}{V o l u m e}$