The present age of a mother is three times that of her daughter. Four years ago, the mother's age was four times the daughter's age. What will be the sum of their present ages (in years)?

Question

The present age of a mother is three times that of her daughter. Four years ago, the mother's age was four times the daughter's age. What will be the sum of their present ages (in years)? (A) 48 (B) 56 (C) 60 (D) 64

Tardigrade Admin · Accepted Answer

Let the present age of the daughter be x years. ∴ text Mother's present age =3 x text years. text Given 3 x-4=4(x-4) ⇒ 3 x-4=4 x-16 ⇒ x=12 ∴ text The sum of their present ages =4 x . = 4(12)=48 text years

Q. The present age of a mother is three times that of her daughter. Four years ago, the mother's age was four times the daughter's age. What will be the sum of their present ages (in years)?

48

56

60

64

Let the present age of the daughter be $x$ years.
$∴ Mother’s present age = 3 x years.$
$Given 3 x - 4 = 4 (x - 4)$
$\Rightarrow 3 x - 4 = 4 x - 16 \Rightarrow x = 12$
$∴ The sum of their present ages = 4 x .$
$= 4 (12) = 48 years$

Q. The present age of a mother is three times that of her daughter. Four years ago, the mother's age was four times the daughter's age. What will be the sum of their present ages (in years)?

48

56

60

64

Let the present age of the daughter be x years. ∴ Mother’s present age =3x years. Given 3x−4=4(x−4) ⇒3x−4=4x−16⇒x=12 ∴ The sum of their present ages =4x. =4(12)=48 years

Let the present age of the daughter be $x$ years.
$∴ Mother’s present age = 3 x years.$
$Given 3 x - 4 = 4 (x - 4)$
$\Rightarrow 3 x - 4 = 4 x - 16 \Rightarrow x = 12$
$∴ The sum of their present ages = 4 x .$
$= 4 (12) = 48 years$