Question

The present age of a mother is three times that of her daughter. Four years ago, the mother's age was four times the daughter's age. What will be the sum of their present ages (in years)?

• A. 48
• B. 56
• C. 60
• D. 64

Answer 1

Answer: (B)

Let the present age of the daughter be $x$ years.
$\therefore \text { Mother's present age }=3 x \text { years. } $
$ \text { Given } 3 x-4=4(x-4)$
$\Rightarrow 3 x-4=4 x-16 \Rightarrow x=12 $
$\therefore \text { The sum of their present ages }=4 x . $
$= 4(12)=48 \text { years }$