The power of a water pump is 5 KW, the amount of water it can raise in 5 minute to a height of 50 m is ( g =10 m / s -2)

Question

The power of a water pump is 5 KW, the amount of water it can raise in 5 minute to a height of 50 m is ( g =10 m / s -2) (A) 5 × 104 L (B) 106 L (C) 3 × 105 L (D) 3 × 106 L

Tardigrade Admin · Accepted Answer

P=(mgh/t)=((ρ × V) g h/t) ⇒ (P × t/ρ × gh)=V V=(5 × 103 × 5 × 60/10-3 × 10 × 50) V=(1500 × 106/500)=3 × 106 L

Q. The power of a water pump is $5 K W$ , the amount of water it can raise in $5$ minute to a height of $50 m$ is $(g = 10 m / s^{- 2})$

$5 \times 1 0^{4} L$

$1 0^{6} L$

$3 \times 1 0^{5} L$

$3 \times 1 0^{6} L$

$P = \frac{m g h}{t} = \frac{( ρ \times V ) g h}{t}$
$\Rightarrow \frac{P \times t}{ρ \times g h} = V$
$V = \frac{5 \times 1 0 ^{3} \times 5 \times 60}{1 0 ^{- 3} \times 10 \times 50}$
$V = \frac{1500 \times 1 0 ^{6}}{500} = 3 \times 1 0^{6} L$

Q. The power of a water pump is 5KW, the amount of water it can raise in 5 minute to a height of 50m is (g=10m/s−2)

5×104L

106L

3×105L

3×106L