the power factor of a series L-C-R circuit when at resonance is

Question

the power factor of a series L-C-R circuit when at resonance is (A) zero (B) 0.5 (C) 1.0 (D) depends on values of L, C and R

Tardigrade Admin · Accepted Answer

Average power of circuit is given by P=E rms × i rms × cos φ In a series LCR circuit at resonance voltage and current being in same phase, therefore φ=0. Hence, power factor = cos φ= cos 0°=1

Q. the power factor of a series L-C-R circuit when at resonance is

zero

0.5

1.0

depends on values of L, C and R

Average power of circuit is given by
$P = E_{r m s} \times i_{r m s} \times cos ϕ$
In a series LCR circuit at resonance voltage and current being in same phase, therefore $ϕ = 0$ .
Hence, power factor $= cos ϕ = cos 0^{\circ} = 1$

Q. the power factor of a series L-C-R circuit when at resonance is

zero

0.5

1.0

depends on values of L, C and R

Average power of circuit is given by P=Erms​×irms​×cosϕ In a series LCR circuit at resonance voltage and current being in same phase, therefore ϕ=0. Hence, power factor =cosϕ=cos0∘=1

Average power of circuit is given by
$P = E_{r m s} \times i_{r m s} \times cos ϕ$
In a series LCR circuit at resonance voltage and current being in same phase, therefore $ϕ = 0$ .
Hence, power factor $= cos ϕ = cos 0^{\circ} = 1$