The potentials of the two plates of capacitors are +10 V and -10 V. The charge on one of the plates is 40 C. The capacitance of the capacitor is:

Question

The potentials of the two plates of capacitors are +10 V and -10 V. The charge on one of the plates is 40 C. The capacitance of the capacitor is: (A) 2 F (B) 4 F (C) 0.5 F (D) 0.25 F

Tardigrade Admin · Accepted Answer

A capacitor is an arrangement which can store sufficient quantity of charge. Suppose, on given a charge q to a conductor, the electric potential of the conductor becomes

V

.
Then, capacitance of capacitor is

C = \frac{q}{V}

The potential difference across the parallel plate capacitor is

10 V - (- 10 V) = 20 V

∴

Capacitance

C = \frac{q}{V} = \frac{40}{20} = 2 F

The unit farad

(F)

is very much bigger unit as capacitance of earth, which is a huge body in the universe has a capacitance of

711 μ F .

So, it is not reasonable to discuss such a bigger unit in questions.

Q. The potentials of the two plates of capacitors are +10V and −10V. The charge on one of the plates is 40C. The capacitance of the capacitor is:

2 F

4 F

0.5 F

0.25 F

Q. The potentials of the two plates of capacitors are $+ 10 V$ and $- 10 V$ . The charge on one of the plates is $40 C$ . The capacitance of the capacitor is: