Question

The potential energy of spring when stretched by a distance x is E. The energy of the spring when stretched by x/2 is

• A. E
• B. E/2
• C. E/4
• D. E/6

Answer 1

Answer: (C)

$\frac{E}{E}=\frac{\frac{1}{2}k{x}^2}{\frac{1}{2}k{\left(\frac{x}{2}\right)}^2}$ $\frac{E}{E}=\frac{4}{1}$ $\Rightarrow$ $E=\frac{E}{4}$