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  4. The potential energy of spring when stretched by a distance x is E. The energy of the spring when stretched by x/2 is

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Q. The potential energy of spring when stretched by a distance x is E. The energy of the spring when stretched by x/2 is

Rajasthan PMTRajasthan PMT 2011

Solution:

$ \frac{E}{E}=\frac{\frac{1}{2}k{{x}^{2}}}{\frac{1}{2}k{{\left( \frac{x}{2} \right)}^{2}}} $ $ \frac{E}{E}=\frac{4}{1} $ $ \Rightarrow $ $ E=\frac{E}{4} $