Question

The potential energy of interaction between the arc of ring of radius $R$ and mass $m$ and the particle of mass $m_0$ placed at centre of curvature is

• A. $-\frac{GM{m}_0}{R}$
• B. $-\frac{GM{m}_0}{6R}$
• C. $-\frac{5}{6}\frac{GM{m}_0}{R}$
• D. $-\frac{GM{m}_0}{2R}$

Answer 1

Answer: (A)

Gravitational potential energy
$U=+m_0\cdot$ potential at origin
$=+m_0\cdot \left(-\frac{GM}{R}\right)$
$U=-\frac{GM{m}_0}{R}$