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Q.
The potential energy of interaction between the arc of ring of radius $R$ and mass $m$ and the particle of mass $m_0$ placed at centre of curvature is
Solution:
Gravitational potential energy
$U = + m_0⋅$ potential at origin
$ =+ m_{0}\cdot\left(-\frac{GM}{R}\right) $
$U =-\frac{GMm_{0}}{R}$
