The potential energy of an electron in He+ ion is -12.09 eV. Indicate in which excited state, the electron is present:

Question

The potential energy of an electron in He+ ion is -12.09 eV. Indicate in which excited state, the electron is present: (A) First (B) Second (C) Third (D) Fourth

Tardigrade Admin · Accepted Answer

P E=2 T E ⇒ -12.09=-2 × 13.6 (z2/n2) ⇒ n2=(2 × 13.6 × 22/12.09)=9 ⇒ n=3 ⇒ Second excited

Q. The potential energy of an electron in $H e^{+}$ ion is $- 12.09 e V$ . Indicate in which excited state, the electron is present:

First

Second

Third

Fourth

$PE = 2 TE$

$\Rightarrow - 12.09 = - 2 \times 13.6 \frac{z ^{2}}{n ^{2}}$

$\Rightarrow n^{2} = \frac{2 \times 13.6 \times 2 ^{2}}{12.09} = 9$

$\Rightarrow n = 3$

$\Rightarrow$ Second excited

Q. The potential energy of an electron in He+ ion is −12.09eV. Indicate in which excited state, the electron is present: