1. Tardigrade
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  3. Chemistry
  4. The potential energy of an electron in He+ ion is -12.09 eV. Indicate in which excited state, the electron is present:

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Q. The potential energy of an electron in $He^+$ ion is $-12.09\,eV$. Indicate in which excited state, the electron is present:

Structure of Atom

Solution:

$P E=2 T E$

$\Rightarrow -12.09=-2 \times 13.6 \frac{z^{2}}{n^{2}}$

$\Rightarrow n^{2}=\frac{2 \times 13.6 \times 2^{2}}{12.09}=9$

$\Rightarrow n=3$

$\Rightarrow $ Second excited