The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

Question

The potential energy of a system is represented in the first figure. The force acting on the system will be represented by <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/00822a6e72b8c749a32368b4444dfc91-.png" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

As slope of problem graph is positive and constant up to certain distance and then it becomes zero. So from F=(-dU/dx),up to distance a, F = constant (negative) and becomes zero suddenly

Q. The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

As slope of problem graph is positive and constant up to certain distance and then it becomes zero.

So from $F = \frac{- d U}{d x},$ up to distance $a, F =$ constant

(negative) and becomes zero suddenly

Q. The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

As slope of problem graph is positive and constant up to certain distance and then it becomes zero. So from F=dx−dU​,up to distance a,F= constant (negative) and becomes zero suddenly

As slope of problem graph is positive and constant up to certain distance and then it becomes zero.

So from $F = \frac{- d U}{d x},$ up to distance $a, F =$ constant

(negative) and becomes zero suddenly