Q.
The potential energy of a spring when stretched through a distance x is 10J. What is the amount of work done on the same spring to stretch it through an additional distance x ?
Potential energy of the spring when stretched through a distance x, U=21kx2=10J
When x becomes 2x, the potential energy will be U′=21k(2x)2=4×21kx2 =4×10=40J ∴ Work done =U′−U=40−10=30J