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Q. The potential energy of a spring when stretched through a distance $x$ is $10\, J$. What is the amount of work done on the same spring to stretch it through an additional distance $x$ ?

Work, Energy and Power

Solution:

Potential energy of the spring when stretched through a distance $x$,
$U = \frac{1}{2}kx^{2} = 10\,J$
When $x$ becomes $2x$, the potential energy will be
$U' = \frac{1}{2}k\left(2x\right)^{2}= 4 \times \frac{1}{2}kx^{2}$
$= 4 \times 10 = 40\,J$
$\therefore $ Work done $= U' - U = 4 0 - 10 = 30 \,J$