Question

The potential energy of a particle $(U_x)$ executing SHM is given by

• A. $U_x=\frac{K}{2}(x-a{)}^2$
• B. $U_x=K_{1}x+K_2{x}^2+K_3{x}^3$
• C. $U_x=A{e}^{-bx}$
• D. $U_x=constant$

Answer 1

Answer: (A)

Correct answer is (a) $U_x=\frac{K}{2}(x-a{)}^2$