The potential energy of a charged parallel plate capacitor is U0. If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

Question

The potential energy of a charged parallel plate capacitor is U0. If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be (A)  (U0/K)  (B)  U0K2  (C) (U0/K2) (D) U02

Tardigrade Admin · Accepted Answer

When a dielectric slab of dielectric constant K is inserted between the plates of charged parallel plate capacitor, then capacity becomes C'=K C potential becomes V'=(V/K) and energy U'=(U/K)

Q. The potential energy of a charged parallel plate capacitor is $U_{0}$ . If a slab of dielectric constant $K$ is inserted between the plates, then the new potential energy will be

$\frac{U _{0}}{K}$

$U_{0} K^{2}$

$\frac{U _{0}}{K ^{2}}$

$U_{0}^{2}$

When a dielectric slab of dielectric constant $K$ is inserted between the plates of charged parallel plate capacitor, then
capacity becomes $C^{'} = K C$
potential becomes $V^{'} = \frac{V}{K}$
and energy $U^{'} = \frac{U}{K}$

Q. The potential energy of a charged parallel plate capacitor is U0​. If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

KU0​​

U0​K2

K2U0​​

U02​