The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an L-C-R circuit . The power factor of this circuit is

Question

The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an L-C-R circuit . The power factor of this circuit is (A) 0.4 (B) 0.5 (C) 0.8 (D) 1.0

Tardigrade Admin · Accepted Answer

cosφ = (VR/Vnet) = (VR/√(VL - VC)2 + VR2) = (80/ √(100-40)2 + 802) = (80/100) = 0.8

Q. The potential differences across the resistance, capacitance and inductance are $80 V$ , $40 V$ and $100 V$ respectively in an $L - C - R$ circuit . The power factor of this circuit is

0.4

0.5

0.8

1.0

$cos ϕ = \frac{V _{R}}{V _{n e t}} = \frac{V _{R}}{( V _{L} - V _{C} ) ^{2} + V _{R^{2}}}$
$= \frac{80}{( 100 - 40 ) ^{2} + 8 0 ^{2}} = \frac{80}{100} = 0.8$

Q. The potential differences across the resistance, capacitance and inductance are 80V, 40V and 100V respectively in an L−C−R circuit . The power factor of this circuit is

0.4

0.5

0.8

1.0

cosϕ=Vnet​VR​​=(VL​−VC​)2+VR2​​VR​​ =(100−40)2+802​80​=10080​=0.8

Q. The potential differences across the resistance, capacitance and inductance are $80 V$ , $40 V$ and $100 V$ respectively in an $L - C - R$ circuit . The power factor of this circuit is

$cos ϕ = \frac{V _{R}}{V _{n e t}} = \frac{V _{R}}{( V _{L} - V _{C} ) ^{2} + V _{R^{2}}}$
$= \frac{80}{( 100 - 40 ) ^{2} + 8 0 ^{2}} = \frac{80}{100} = 0.8$