The potential difference between the ends of a resistance R is VR, between the ends of capacitor is VC = 2VR and between the ends of inductance is VL = 3VR then the alternating potential0 of the source in terms of VR will be

Question

The potential difference between the ends of a resistance R is VR, between the ends of capacitor is VC = 2VR and between the ends of inductance is VL = 3VR then the alternating potential0 of the source in terms of VR will be (A) √2VR (B) VR (C) (VR/√2) (D) 5VR

Tardigrade Admin · Accepted Answer

Vs =VB +Vc +VL =VR i-VR j +3 Vr j VR i+VR j =√2VR

Q. The potential difference between the ends of a resistance R is $V_{R}$ , between the ends of capacitor is $V_{C} = 2 V_{R}$ and between the ends of inductance is $V_{L} = 3 V_{R}$ then the alternating potential0 of the source in terms of $V_{R}$ will be

$2 V_{R}$

$V_{R}$

$\frac{V _{R}}{2}$

$5 V_{R}$

$V_{s} = V_{B} + V_{c} + V_{L} = V_{R} i - V_{R} j + 3 V_{r} j$
$V_{R} i + V_{R} j$ $= 2 V_{R}$

Q. The potential difference between the ends of a resistance R is VR​, between the ends of capacitor is VC​=2VR​ and between the ends of inductance is VL​=3VR​ then the alternating potential0 of the source in terms of VR​ will be

2​VR​

VR​

2​VR​​

5VR​