The potential difference between the cathode and the target in a Coolidge tube is 120 kV. What can be the minimum wavelength (in overset0 mathopA ) of the X-rays emitted by this tube?

Question

The potential difference between the cathode and the target in a Coolidge tube is 120 kV. What can be the minimum wavelength (in overset0 mathopA ) of the X-rays emitted by this tube? (A) 0.4 overset0 mathopA  (B) 0.3 overset0 mathopA  (C) 0.2 overset0 mathopA  (D) 0.1 overset0 mathopA

Tardigrade Admin · Accepted Answer

Here: potential difference V=120 kV=120× 103V From the formula for minimum wavelength λ min =(hc/eV)=(6.6× 10-34× 3× 108/(1.6× 10-19)× 120× 103)=0.1 overset texto mathop textA

Q. The potential difference between the cathode and the target in a Coolidge tube is 120 kV. What can be the minimum wavelength (in $A 0$ ) of the X-rays emitted by this tube?

0.4 $A 0$

0.3 $A 0$

0.2 $A 0$

0.1 $A 0$

Here: potential difference $V = 120 kV = 120 \times 10^{3} V$ From the formula for minimum wavelength $λ_{m i n} = \frac{h c}{e V} = \frac{6.6 \times 10 ^{- 34} \times 3 \times 10 ^{8}}{( 1.6 \times 10 ^{- 19} ) \times 120 \times 10 ^{3}} = 0.1 A o$

Q. The potential difference between the cathode and the target in a Coolidge tube is 120 kV. What can be the minimum wavelength (in A0 ) of the X-rays emitted by this tube?

0.4 A0

0.3 A0

0.2 A0

0.1 A0