The potential difference across a resistor is measured to be V=(.8±0.5.) V and the current through it is measured to be I=(.2±0.2.) A , then the value of the resistance R is

Question

The potential difference across a resistor is measured to be V=(.8±0.5.) V and the current through it is measured to be I=(.2±0.2.) A , then the value of the resistance R is (A) 4±16.25 % (B) 4±6.25 % (C) 4±10 % (D) 4±8 %

Tardigrade Admin · Accepted Answer

V=(.8+0.5.) I=(.2+0.2.) R=(8/2)=4 (Δ R/R) %=((Δ V/V) + (Δ I/I)) =((0.5/8) + (0.2/2))× 100=16.25 % ∴ R=(.4±16.25 %.)

Q. The potential difference across a resistor is measured to be $V = (8 \pm 0.5) V$ and the current through it is measured to be $I = (2 \pm 0.2) A$ , then the value of the resistance $R$ is

$4 \pm 16.25%$

$4 \pm 6.25%$

$4 \pm 10%$

$4 \pm 8%$

$V = (8 + 0.5)$
$I = (2 + 0.2)$
$R = \frac{8}{2} = 4$
$\frac{Δ R}{R} % = (\frac{Δ V}{V} + \frac{Δ I}{I})$
$= (\frac{0.5}{8} + \frac{0.2}{2}) \times 100 = 16.25%$
$∴ R = (4 \pm 16.25%)$

Q. The potential difference across a resistor is measured to be V=(8±0.5)V and the current through it is measured to be I=(2±0.2)A , then the value of the resistance R is

4±16.25%

4±6.25%

4±10%

4±8%