Question

The potential barrier developed in the diode shown in figure below is $0.5V$. The current through the diode is

• A. 45 mA
• B. 40 mA
• C. 30 mA
• D. 20 mA

Answer 1

Answer: (C)

$I=\frac{5-0.5}{150}A=\frac{4.5}{150}A$
$=0.03A=30mA$