The potential at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively

Question

The potential at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively (A) 90° and 180° (B) 0° and 90° (C) 90° and 0° (D) 0° and 180°

Tardigrade Admin · Accepted Answer

V=(k p cos θ/r2) . If θ=0° then V= max If θ=180° then V= min .

Q. The potential at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively

$9 0^{\circ}$ and $18 0^{\circ}$

$0^{\circ}$ and $9 0^{\circ}$

$9 0^{\circ}$ and $0^{\circ}$

$0^{\circ}$ and $18 0^{\circ}$

$V = \frac{k p c o s θ}{r ^{2}} .$
If $θ = 0^{\circ}$ then $V = max$
If $θ = 18 0^{\circ}$ then $V = min .$

Q. The potential at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively

90∘ and 180∘

0∘ and 90∘

90∘ and 0∘

0∘ and 180∘

V=r2kpcosθ​. If θ=0∘ then V=max If θ=180∘ then V=min.

$9 0^{\circ}$ and $18 0^{\circ}$

$0^{\circ}$ and $9 0^{\circ}$

$9 0^{\circ}$ and $0^{\circ}$

$0^{\circ}$ and $18 0^{\circ}$

$V = \frac{k p c o s θ}{r ^{2}} .$
If $θ = 0^{\circ}$ then $V = max$
If $θ = 18 0^{\circ}$ then $V = min .$