The position x of a particle moving along x-axis at time (t) is given by the equation t=√x+2, where x is in metres and t in seconds. Find the work done by the force in first four seconds.

Question

The position x of a particle moving along x-axis at time (t) is given by the equation t=√x+2, where x is in metres and t in seconds. Find the work done by the force in first four seconds. (A) Zero (B) 2 J (C) 4 J (D) 8 J

Tardigrade Admin · Accepted Answer

x =(t-2)2 (d x/d t) =v=2(t-2) W =(1/2) m v2-(1/2) m u2 =(m/2)[42-42]=0

Q. The position $x$ of a particle moving along $x$ -axis at time $(t)$ is given by the equation $t = x + 2$ , where $x$ is in metres and $t$ in seconds. Find the work done by the force in first four seconds.

Zero

2 J

4 J

8 J

$x = (t - 2)^{2}$
$\frac{d x}{d t} = v = 2 (t - 2)$
$W = \frac{1}{2} m v^{2} - \frac{1}{2} m u^{2}$
$= \frac{m}{2} [4^{2} - 4^{2}] = 0$

Q. The position x of a particle moving along x-axis at time (t) is given by the equation t=x​+2, where x is in metres and t in seconds. Find the work done by the force in first four seconds.

Zero

2 J

4 J

8 J

x=(t−2)2 dtdx​=v=2(t−2) W=21​mv2−21​mu2 =2m​[42−42]=0

Q. The position $x$ of a particle moving along $x$ -axis at time $(t)$ is given by the equation $t = x + 2$ , where $x$ is in metres and $t$ in seconds. Find the work done by the force in first four seconds.

$x = (t - 2)^{2}$
$\frac{d x}{d t} = v = 2 (t - 2)$
$W = \frac{1}{2} m v^{2} - \frac{1}{2} m u^{2}$
$= \frac{m}{2} [4^{2} - 4^{2}] = 0$