Question

The position-time $(x-t)$ graphs for two children $A$ and $B$ returning from their school $O$ to their homes $P$ and $Q$ respectively along a straight path (taken as $x$ -axis) are shown in the figure below. Choose the incorrect option.

• A. $A$ lives closer to the school than $B$
• B. $A$ starts from the school earlier than $B$
• C. $A$ and $B$ have equal average velocities from $0$ to $t_0$
• D. $B$ overtakes $A$ on the way

Answer 1

Answer: (C)

$X_B>X_A$
So $A$ lives closer option (i) is correct
$A$ starts at $t=0$ while B at $t=t_0$
So $A$ starts early
option (ii) is also correct
For average velocity to be same, the slope of both line should be the same which is not the case so (iii) is wrong.
We can clearly see at the point of intersection of two graph (ii) overtakes (i) so (iv) is also correct.