The position-time graph of a particle of mass 4 kg is shown in the figure. Calculate the impulse (in MKS units) at time t = 0 and t = 6 seconds respectively

Question

The position-time graph of a particle of mass 4 kg is shown in the figure. Calculate the impulse (in MKS units) at time t = 0 and t = 6 seconds respectively <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/c6dcf125573bc6b707d9f8e081b3cd25-.png" /> (A) +6.31 and - 6.31 (B) +3.33 and -3.33 (C) +6.33 and -6.33 (D) +3.25 and -3.25

Tardigrade Admin · Accepted Answer

The position-time graph gives the velocity

According to this graph, velocity at

t = 6 s

v = \frac{5}{6} m / s

Impulse

=

Change in momentum

= m_{1} v_{2} - m_{2} v_{1}

= 4 \times 5/6 - 4 \times 0

= 20/6 = 3.33

So option (b) is correct.

Q. The position-time graph of a particle of mass 4kg is shown in the figure. Calculate the impulse (in MKS units) at time t=0 and t=6 seconds respectively

+6.31 and - 6.31

+3.33 and -3.33

+6.33 and -6.33

+3.25 and -3.25

The position-time graph gives the velocity According to this graph, velocity at t=6s v=65​m/s Impulse = Change in momentum =m1​v2​−m2​v1​ =4×5/6−4×0 =20/6=3.33 So option (b) is correct.

Q. The position-time graph of a particle of mass $4 k g$ is shown in the figure. Calculate the impulse (in $M K S$ units) at time $t = 0$ and $t = 6$ seconds respectively

The position-time graph gives the velocity

According to this graph, velocity at $t = 6 s$
$v = \frac{5}{6} m / s$
Impulse $=$ Change in momentum
$= m_{1} v_{2} - m_{2} v_{1}$
$= 4 \times 5/6 - 4 \times 0$
$= 20/6 = 3.33$
So option (b) is correct.